CUET · PHYSICS · PYQ PAPER 2025
If 200 MeV energy is released in the fission of a single nucleus of uranium-235, how many fissions per second will produce a power of 32 kW?
- A \( 10^{13} \)
- B \( 10^{15} \)
- C \( 10^{19} \)
- D \( 10^{21} \)
Answer & Solution
Correct Answer
(B) \( 10^{15} \)
Step-by-step Solution
Detailed explanation
\( E = 200 \text{ MeV} = 200 \times 1.6 \times 10^{-13} \text{ J} = 3.2 \times 10^{-11} \text{ J} \) \( P = 32 \text{ kW} = 32 \times 10^3 \text{ W} \) \( N = \frac{P}{E} = \frac{32 \times 10^3}{3.2 \times 10^{-11}} = 10 \times 10^{14} = 10^{15} \)
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