CUET · PHYSICS · PYQ PAPER 2023
Graphs were plotted between stopping potential \( (V_o) \) and frequency of incident radiation \( (\nu) \) for 2 metals namely Cesium (work fn. 2.14) and Aluminium (work fn. 4.28). The ratio of slope of graph of Cesium to the slope of graph for Aluminium is:
- A \( 2 \)
- B \( 1/2 \)
- C \( 1 \)
- D \( 1.5 \)
Answer & Solution
Correct Answer
(C) \( 1 \)
Step-by-step Solution
Detailed explanation
\( V_o = \frac{h}{e}\nu - \frac{\phi}{e} \) Slope \( = \frac{h}{e} \) Ratio \( = \frac{(h/e)_{Cesium}}{(h/e)_{Aluminium}} = \frac{h/e}{h/e} = 1 \)
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