CUET · PHYSICS · PYQ PAPER 2025
Four identical bulbs are connected in series with a source. These together dissipate a power P. The power dissipated, if the four bulbs are connected in parallel with the same source, will be
- A P/4
- B P/16
- C 4 P
- D 16 P
Answer & Solution
Correct Answer
(D) 16 P
Step-by-step Solution
Detailed explanation
\( R_{series} = 4R \) \( P = \frac{V^2}{4R} \) \( R_{parallel} = \frac{R}{4} \) \( P_{new} = \frac{V^2}{R_{parallel}} = \frac{V^2}{R/4} = \frac{4V^2}{R} \) \( P_{new} = 4 \left( \frac{V^2}{R} \right) = 4(4P) = 16P \)
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