CUET · PHYSICS · PYQ PAPER 2023
Four equal charges \(Q\) are placed at the four corners of a square of side 'a'. Work done in removing a charge \(-Q\) from its centre to infinity is :
- A zero
- B \(\frac{\sqrt{2} Q^2}{4 \pi \varepsilon_0 a}\)
- C \(\frac{\sqrt{2} Q^2}{\pi \varepsilon_0 a}\)
- D \(\frac{-Q^2 \sqrt{2}}{2 \pi \varepsilon_0 a}\)
Answer & Solution
Correct Answer
(C) \(\frac{\sqrt{2} Q^2}{\pi \varepsilon_0 a}\)
Step-by-step Solution
Detailed explanation
\( r = \frac{a\sqrt{2}}{2} \) \( V_c = 4 \times \frac{Q}{4\pi\varepsilon_0 r} = 4 \times \frac{Q}{4\pi\varepsilon_0 (a\sqrt{2}/2)} = \frac{\sqrt{2}Q}{\pi\varepsilon_0 a} \)…
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