CUET · PHYSICS · PYQ PAPER 2025
For an AC circuit, a phase diagram shows emf on X-axis, and current I is at angle \( \theta \) to emf. Angle \( \theta \) is phase angle between emf and current. Current I is resolved into two components, \( I \cos \theta \) is along emf on X-axis. \( I \sin \theta \) is along perpendicular direction to emf.
(A) Component \( I \cos \theta \) will draw the power from the source
(B) Component \( I \sin \theta \) will draw the power from the source
(C) \( I \cos \theta \) is called the powerless current
(D) \( I \sin \theta \) is called the powerless current
Choose the correct answer from the options given below:
- A (B) and (C) only
- B (A) and (C) only
- C (C) and (D) only
- D (A) and (D) only
Answer & Solution
Correct Answer
(D) (A) and (D) only
Step-by-step Solution
Detailed explanation
(A) True: \( P = E I \cos \theta \). The component \( I \cos \theta \) is in phase with emf and contributes to average power. (B) False: The component \( I \sin \theta \) is 90° out of phase with emf, leading to zero average power drawn. (C) False: \( I \cos \theta \) is called…
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