CUET · PHYSICS · PYQ PAPER 2025

For a photosensitive surface, work function is \( 3.3 \times 10^{-19} \, \text{J} \). Taking Planck's constant to be \( 6.6 \times 10^{-34} \, \text{Js} \), the threshold frequency would be:

A \( 6 \times 10^{13} \, \text{Hz} \)
B \( 2 \times 10^{12} \, \text{Hz} \)
C \( 5.0 \times 10^{14} \, \text{Hz} \)
D \( 1.8 \times 10^{12} \, \text{Hz} \)

Verified Solution

Answer & Solution

Correct Answer

(C) \( 5.0 \times 10^{14} \, \text{Hz} \)

Step-by-step Solution

Detailed explanation

\( f_0 = \frac{\phi}{h} \) \( f_0 = \frac{3.3 \times 10^{-19} \, \text{J}}{6.6 \times 10^{-34} \, \text{Js}} \) \( f_0 = 5.0 \times 10^{14} \, \text{Hz} \)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List-I with List-II

List-I (Physical Quantity) (According to Rutherford Model)	List-II (Formula)
(A) Total energy of the electron in hydrogen atom	(I) \( \frac{e^2}{8\pi\varepsilon_ R} \)
(B) Kinetic energy of the electron in hydrogen atom	(II) \( \frac{-e^2}{8\pi\varepsilon_ R} \)
(C) Radius of the circular orbit around the nucleus	(III) \( \frac{-e^2}{4\pi\varepsilon_ R} \)
(D) Potential energy of the electron in hydrogen atom	(IV) \( \frac{e^2}{4\pi\varepsilon_ m v^2} \)

Choose the correct answer from the options given below :

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