CUET · PHYSICS · PYQ PAPER 2023
For a coil of 5 turns, the magnetic flux varies with time as \( \phi_{B}(t) = (2t^3 - \frac{5}{2}t^2 + t) \), where \( \phi_{B}(t) \) and t are in S.I. units. The induced current at t = 2 s in the coil, if its total resistance is 150 \( \Omega \), is :
- A 5.0 A
- B 0.5 A
- C 0.05 A
- D 2.0 A
Answer & Solution
Correct Answer
(B) 0.5 A
Step-by-step Solution
Detailed explanation
\( \frac{d\phi_B}{dt} = 6t^2 - 5t + 1 \) \( \frac{d\phi_B}{dt}\Big|_{t=2s} = 6(2)^2 - 5(2) + 1 = 15 \) Wb/s \( \mathcal{E} = -N \frac{d\phi_B}{dt} = -5 \times 15 = -75 \) V \( I = \frac{|\mathcal{E}|}{R} = \frac{75}{150} = 0.5 \) A
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