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CUET · PHYSICS · PYQ PAPER 2025


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Figure shows a rectangular conductor PQRS in which the conductor PQ is free to move. The conductor PQ is moved towards the left with a constant velocity V as shown in the figure. Assume that there is no loss of energy due to friction. What will be the magnetic flux linked with the loop PQRS and the motional emf?

  1. A Magnetic \( flux = Bl(xV) \); Motional \( emf = Blx \)
  2. B Magnetic \( flux = Blx \); Motional \( emf = (BlV)/t \)
  3. C Magnetic flux = Blx: Motional emf = BlV
  4. D Magnetic flux \(=B /(l x)\); Motional \( emf = BlV \)
Verified Solution

Answer & Solution

Correct Answer

(C) Magnetic flux = Blx: Motional emf = BlV

Step-by-step Solution

Detailed explanation

Magnetic flux \( \Phi_B = B \times (\text{Area}) = B(lx) = Blx \) Motional emf \( \epsilon = \left| \frac{d\Phi_B}{dt} \right| = \left| \frac{d(Blx)}{dt} \right| = \left| Bl \frac{dx}{dt} \right| \) Since \( \left| \frac{dx}{dt} \right| = V \), \( \epsilon = BlV \)