CUET · PHYSICS · PYQ PAPER 2025

Figure shows a rectangular conductor PQRS in which the conductor PQ is free to move. The conductor PQ is moved towards the left with a constant velocity V as shown in the figure. Assume that there is no loss of energy due to friction. What will be the magnetic flux linked with the loop PQRS and the motional emf?
- A Magnetic \( flux = Bl(xV) \); Motional \( emf = Blx \)
- B Magnetic \( flux = Blx \); Motional \( emf = (BlV)/t \)
- C Magnetic flux = Blx: Motional emf = BlV
- D Magnetic flux \(=B /(l x)\); Motional \( emf = BlV \)
Answer & Solution
Correct Answer
(C) Magnetic flux = Blx: Motional emf = BlV
Step-by-step Solution
Detailed explanation
Magnetic flux \( \Phi_B = B \times (\text{Area}) = B(lx) = Blx \) Motional emf \( \epsilon = \left| \frac{d\Phi_B}{dt} \right| = \left| \frac{d(Blx)}{dt} \right| = \left| Bl \frac{dx}{dt} \right| \) Since \( \left| \frac{dx}{dt} \right| = V \), \( \epsilon = BlV \)
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