CUET · PHYSICS · PYQ PAPER 2023
Energy of a photon corresponding to a wavelength of 600 nm is 2.08 eV. The energy of a photon of wavelength 400 nm will be :
- A 1.39 eV
- B 3.12 eV
- C 4.68 eV
- D 0.92 eV
Answer & Solution
Correct Answer
(B) 3.12 eV
Step-by-step Solution
Detailed explanation
\(E \propto \frac{1}{\lambda}\) \(E_2 = E_1 \times \frac{\lambda_1}{\lambda_2}\) \(E_2 = 2.08 \text{ eV} \times \frac{600 \text{ nm}}{400 \text{ nm}}\) \(E_2 = 3.12 \text{ eV}\)
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