CUET · PHYSICS · PYQ PAPER 2025
Eight cells each having emf 2 V and internal resistance \( r = 0.02 \Omega \) are connected in series with an external resistance 9 \( \Omega \). The current flowing through the external resistance (I) is
- A 1.60 A
- B 0.99 A
- C 1.75 A
- D 1.88 A
Answer & Solution
Correct Answer
(C) 1.75 A
Step-by-step Solution
Detailed explanation
\( E_{total} = 8 \times 2 = 16 \, V \) \( r_{total} = 8 \times 0.02 = 0.16 \, \Omega \) \( I = \frac{E_{total}}{R_{ext} + r_{total}} = \frac{16}{9 + 0.16} = \frac{16}{9.16} \approx 1.75 \, A \)
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