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CUET · PHYSICS · PYQ PAPER 2025

Eight cells each having emf 2 V and internal resistance \( r = 0.02 \Omega \) are connected in series with an external resistance 9 \( \Omega \). The current flowing through the external resistance (I) is

  1. A 1.60 A
  2. B 0.99 A
  3. C 1.75 A
  4. D 1.88 A
Verified Solution

Answer & Solution

Correct Answer

(C) 1.75 A

Step-by-step Solution

Detailed explanation

\( E_{total} = 8 \times 2 = 16 \, V \) \( r_{total} = 8 \times 0.02 = 0.16 \, \Omega \) \( I = \frac{E_{total}}{R_{ext} + r_{total}} = \frac{16}{9 + 0.16} = \frac{16}{9.16} \approx 1.75 \, A \)
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