CUET · PHYSICS · PYQ PAPER 2023
Density of electrons in an n-type semiconductor is \( 10^{19} \text{ m}^{-3} \). If the drift velocity is 0.02 mm/s, when an electric field \( 1.33 \times 10^{-5} \text{ V/m} \) is applied. Find the resistivity of semiconductor [contribution of holes is ignored]
- A \( 1 \ \Omega \text{ m} \)
- B \( 2 \ \Omega \text{ m} \)
- C \( 0.2 \ \Omega \text{ m} \)
- D \( 0.4 \ \Omega \text{ m} \)
Answer & Solution
Correct Answer
(D) \( 0.4 \ \Omega \text{ m} \)
Step-by-step Solution
Detailed explanation
\( \rho = \frac{E}{nev_d} \) \( \rho = \frac{1.33 \times 10^{-5} \text{ V/m}}{(10^{19} \text{ m}^{-3})(1.6 \times 10^{-19} \text{ C})(0.02 \times 10^{-3} \text{ m/s})} \) \( \rho = \frac{1.33 \times 10^{-5}}{3.2 \times 10^{-5}} \ \Omega \text{ m} \)…
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