CUET · PHYSICS · PYQ PAPER 2025
Current and voltage in an a. c. circuit are given as
\( I = 10 \sin(50t -
\frac{\pi}{2}) \text{ A} \)
\( V = 200 \sin(50t) \text{ V} \) (t represents time)
The power dissipated in the circuit is
- A 2000 W
- B 20 W
- C 0 W
- D 40 W
Answer & Solution
Correct Answer
(C) 0 W
Step-by-step Solution
Detailed explanation
\( V_0 = 200 \text{ V}, I_0 = 10 \text{ A} \) \( \phi = 0 - (-\frac{\pi}{2}) = \frac{\pi}{2} \) \( P = \frac{V_0 I_0}{2} \cos(\phi) = \frac{200 \times 10}{2} \cos(\frac{\pi}{2}) = 1000 \times 0 = 0 \text{ W} \)
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