CUET · PHYSICS · PYQ PAPER 2025
Bulb B1 is a 50 W bulb working on 100 V and Bulb B2 is a 200 W bulb also working on 100 V. The ratio of resistances of bulbs B1 to B2 is:
- A \(4:1\)
- B \(4:5\)
- C \(8:1\)
- D \(2:1\)
Answer & Solution
Correct Answer
(A) \(4:1\)
Step-by-step Solution
Detailed explanation
\(R_1 = \frac{V^2}{P_1} = \frac{(100\,V)^2}{50\,W} = 200\,\Omega\) \(R_2 = \frac{V^2}{P_2} = \frac{(100\,V)^2}{200\,W} = 50\,\Omega\) \(R_1 : R_2 = 200 : 50 = 4:1\)
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