ExamBro
ExamBro
CUET · PHYSICS · PYQ PAPER 2025

At some instant, the current in the circuit shown below is 1 A, and it is decreasing at a rate of \( 10^2 \text{ A/s} \). The value of the potential difference \( (V_P - V_Q) \) at that instant is:
image

  1. A 33 V
  2. B 120 V
  3. C 23 V
  4. D 66 V
Verified Solution

Answer & Solution

Correct Answer

(C) 23 V

Step-by-step Solution

Detailed explanation

\( V_P - V_Q = IR + L\frac{dI}{dt} \) \( V_P - V_Q = (1 \text{ A})(33 \, \Omega) + (0.1 \text{ H})(-10^2 \text{ A/s}) \) \( V_P - V_Q = 33 \text{ V} - 10 \text{ V} \) \( V_P - V_Q = 23 \text{ V} \)
From CUET
Explore more questions on app