CUET · PHYSICS · PYQ PAPER 2025
At some instant, the current in the circuit shown below is 1 A, and it is decreasing at a rate of \( 10^2 \text{ A/s} \). The value of the potential difference \( (V_P - V_Q) \) at that instant is:

- A 33 V
- B 120 V
- C 23 V
- D 66 V
Answer & Solution
Correct Answer
(C) 23 V
Step-by-step Solution
Detailed explanation
\( V_P - V_Q = IR + L\frac{dI}{dt} \) \( V_P - V_Q = (1 \text{ A})(33 \, \Omega) + (0.1 \text{ H})(-10^2 \text{ A/s}) \) \( V_P - V_Q = 33 \text{ V} - 10 \text{ V} \) \( V_P - V_Q = 23 \text{ V} \)
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