CUET · PHYSICS · PYQ PAPER 2025
At room temperature (\(25.0^\circ C\)) the resistance of a heating element is \(100 \Omega\). The temperature of the element at which resistance becomes \(125.5 \Omega\) is : (Given that the temperature coefficient of the material of the resistor is \(1.70 \times 10^{-4} \text{ } ^\circ C^{-1}\))
- A \(1525^\circ C\)
- B \(1500^\circ C\)
- C \(1475^\circ C\)
- D 1500 K
Answer & Solution
Correct Answer
(A) \(1525^\circ C\)
Step-by-step Solution
Detailed explanation
\( R = R_0 [1 + \alpha (T - T_0)] \) \( T = T_0 + \frac{1}{\alpha} \left( \frac{R}{R_0} - 1 \right) \) \( T = 25.0^\circ C + \frac{1}{1.70 \times 10^{-4} \text{ } ^\circ C^{-1}} \left( \frac{125.5 \Omega}{100 \Omega} - 1 \right) \)…
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