CUET · PHYSICS · PYQ PAPER 2023
At a place, the horizontal component of earth's magnetic field is \( 4 \times 10^{-4} \text{ T} \) and angle of dip is \( 60^\circ \). The value of horizontal component of earth's magnetic field at the equator is :
- A \( \sqrt{2} \times 10^{-4} \text{ T} \)
- B \( 2 \times 10^{-4} \text{ T} \)
- C Zero
- D \( 8 \times 10^{-4} \text{ T} \)
Answer & Solution
Correct Answer
(D) \( 8 \times 10^{-4} \text{ T} \)
Step-by-step Solution
Detailed explanation
\( H_{eq} = \frac{H}{\cos \delta} \) \( H_{eq} = \frac{4 \times 10^{-4}}{\cos 60^\circ} = \frac{4 \times 10^{-4}}{0.5} = 8 \times 10^{-4} \text{ T} \)
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