ExamBro
ExamBro
CUET · PHYSICS · PYQ PAPER 2025

AOB is a right angled triangle. Charges \( Q_1 \) and \( Q_2 \) are placed as shown. If the resultant electric field at O is perpendicular to the hypotenuse then \( \frac{Q_1}{Q_2} \) is proportional to :
image

  1. A \( \frac{x_1}{x_2} \)
  2. B \( \frac{x_2}{x_1} \)
  3. C \( \frac{x_1^2}{x_2^2} \)
  4. D \( \frac{x_2^2}{x_1^2} \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( \frac{x_1}{x_2} \)

Step-by-step Solution

Detailed explanation

\( \vec{E_1} = k \frac{Q_1}{x_1^2} \hat{i} \) \( \vec{E_2} = -k \frac{Q_2}{x_2^2} \hat{j} \) \( \vec{E_{res}} = k \left( \frac{Q_1}{x_1^2} \hat{i} - \frac{Q_2}{x_2^2} \hat{j} \right) \) \( \vec{AB} = x_1 \hat{i} + x_2 \hat{j} \) \( \vec{E_{res}} \cdot \vec{AB} = 0 \)…