CUET · PHYSICS · PYQ PAPER 2025
An unpolarized light of intensity \(I_0\) is passed through a polariser and is incident on an analyser making an angle of \((\pi/6) \text{ rad}\) with that of the polariser. The intensity of the light transmitted from the analyzer is
- A \(0.33 I_0\)
- B \(0.5 I_0\)
- C \(0.375 I_0\)
- D \(0.75 I_0\)
Answer & Solution
Correct Answer
(C) \(0.375 I_0\)
Step-by-step Solution
Detailed explanation
\(I_p = I_0 / 2\) \(I_A = I_p \cos^2 (\pi/6)\) \(I_A = (I_0/2) (\sqrt{3}/2)^2\) \(I_A = (I_0/2) (3/4)\) \(I_A = 0.375 I_0\)
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