CUET · PHYSICS · PYQ PAPER 2023
An ordinary light of intensity \(I_0\) is passed through a polaroid \(P_1\) which is crossed with another polaroid \(P _{ 2 }\). Now a third polaroid is placed in between \(P _1\) and \(P _2\) with its pass aris making an angle \(\beta\) with the pass axis of \(P_1\). The value of \(\beta\) for which the intensity of light from \(P_2\) is \(\frac{I_0}{8}\) is :
- A \(0^{\circ}\)
- B \(90^{\circ}\)
- C \(60^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(D) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
\(I_1 = \frac{I_0}{2}\) \(I_3 = I_1 \cos^2 \beta = \frac{I_0}{2} \cos^2 \beta\) Angle between P3 and P2 is \((90^{\circ} - \beta)\) \(I_2 = I_3 \cos^2 (90^{\circ} - \beta) = I_3 \sin^2 \beta\) \(\frac{I_0}{8} = \left(\frac{I_0}{2} \cos^2 \beta\right) \sin^2 \beta\)…
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