CUET · PHYSICS · PYQ PAPER 2025
An oil drop of mass m carrying a charge +q is held stationary in air by an electric field E. The electric field is correctly given by
- A E = mg/q acting upwards
- B E = mg/q acting downwards
- C E = q/mg acting upwards
- D E = q/mg acting downwards
Answer & Solution
Correct Answer
(A) E = mg/q acting upwards
Step-by-step Solution
Detailed explanation
For equilibrium, \( qE = mg \) \( E = \frac{mg}{q} \) acting upwards
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