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CUET · PHYSICS · PYQ PAPER 2025

An inductor of 500 mH is in series with a resistance and a variable capacitor connected to a source of frequency 0.4 kHz. The value of capacitance of the capacitor to get a maximum current will be

  1. A \( 2.3 \mu F \)
  2. B \( 0.32 \mu F \)
  3. C \( 63 \mu F \)
  4. D \( 0.62 \mu F \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( 0.32 \mu F \)

Step-by-step Solution

Detailed explanation

For maximum current (resonance): \( X_L = X_C \) \( 2\pi f L = \frac{1}{2\pi f C} \) \( C = \frac{1}{(2\pi f)^2 L} \) \( C = \frac{1}{(2\pi \times 0.4 \times 10^3 \, \text{Hz})^2 \times 0.5 \, \text{H}} \) \( C = \frac{1}{(800\pi)^2 \times 0.5} \, \text{F} \)…