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CUET · PHYSICS · PYQ PAPER 2025

An electron placed in a magnetic field of \( 3.14 \times 10^{-4} \, \text{T} \) moves in a circle. The frequency of the revolution of the electron is:

  1. A \( 8.79 \times 10^6 \, \text{Hz} \)
  2. B \( 8.79 \times 10^5 \, \text{Hz} \)
  3. C \( 6.08 \times 10^6 \, \text{Hz} \)
  4. D \( 2.8 \times 10^6 \, \text{Hz} \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( 8.79 \times 10^6 \, \text{Hz} \)

Step-by-step Solution

Detailed explanation

\( f = \frac{eB}{2\pi m_e} \) \( f = \frac{(1.602 \times 10^{-19} \, \text{C}) \times (3.14 \times 10^{-4} \, \text{T})}{2\pi \times (9.109 \times 10^{-31} \, \text{kg})} \) \( f = 8.79 \times 10^6 \, \text{Hz} \)
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