CUET · PHYSICS · PYQ PAPER 2023
An electron moves around the nucleus in a hydrogen atom of radius 0.05 nm with a velocity of \( 2 \times 10^6 \text{ m s}^{-1} \). The magnetic field produced at the centre of the nucleus is:
- A 0.128 T
- B 6.4 T
- C 128 T
- D 12.8 T
Answer & Solution
Correct Answer
(D) 12.8 T
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0 e v}{4 \pi r^2} \) \( B = \frac{(4 \pi \times 10^{-7} \text{ T m A}^{-1})(1.602 \times 10^{-19} \text{ C})(2 \times 10^6 \text{ m s}^{-1})}{4 \pi (0.05 \times 10^{-9} \text{ m})^2} \) \( B = \frac{3.204 \times 10^{-20}}{25 \times 10^{-22}} = 12.816 \text{ T} \)
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