CUET · PHYSICS · PYQ PAPER 2025
An electron is projected into a magnetic field of flux density \( 10 \text{ Wb/m}^2 \) with a velocity of \( 3 \times 10^7 \text{ m/s} \) at an angle of \( 30^{\circ} \) to the field. The magnetic force on the electron is:
- A \( 1.6 \times 10^{-11} \text{ N} \)
- B \( 4.8 \times 10^{-11} \text{ N} \)
- C \( 2.4 \times 10^{-11} \text{ N} \)
- D \( 9.2 \times 10^{-11} \text{ N} \)
Answer & Solution
Correct Answer
(C) \( 2.4 \times 10^{-11} \text{ N} \)
Step-by-step Solution
Detailed explanation
\( F = qvB \sin\theta \) \( F = (1.6 \times 10^{-19} \text{ C})(3 \times 10^7 \text{ m/s})(10 \text{ Wb/m}^2) \sin(30^{\circ}) \) \( F = (1.6 \times 10^{-19})(3 \times 10^7)(10)(0.5) \text{ N} \) \( F = 2.4 \times 10^{-11} \text{ N} \)
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