CUET · PHYSICS · PYQ PAPER 2025
An electron is moving at a velocity of \( 3.2 \times 10^{7} \text{ m/s} \) in a magnetic field along a circular path of radius 20 cm. The magnitude of the magnetic field applied is (approximately)
- A \( 1.6 \times 10^{-4} \text{ T} \)
- B \( 8 .43 \times 10^{-5} \text{ T} \)
- C \( 9 \times 10^{-4} \text{ T} \)
- D \( 9 \times 10^{-5} \text{ T} \)
Answer & Solution
Correct Answer
(C) \( 9 \times 10^{-4} \text{ T} \)
Step-by-step Solution
Detailed explanation
\( B = \frac{mv}{qr} \) \( B = \frac{(9.109 \times 10^{-31} \text{ kg})(3.2 \times 10^{7} \text{ m/s})}{(1.602 \times 10^{-19} \text{ C})(0.20 \text{ m})} \) \( B \approx 9.1 \times 10^{-4} \text{ T} \)
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