CUET · PHYSICS · PYQ PAPER 2025
An electron is moving at a velocity of 100 m/s along the X-axis in the presence of an electric field of 30 V/m directed along the Y-axis and a magnetic field of 300 G directed along the Z axis. The magnitude and direction of force acting on the electron is (Given: the charge on the electron is "e")
- A 33 e N along the Y-axis
- B 30 e N along the negative Y-axis
- C 27 e N along the Y-axis
- D 27 e N along the negative Y-axis
Answer & Solution
Correct Answer
(D) 27 e N along the negative Y-axis
Step-by-step Solution
Detailed explanation
\( \vec{F}_E = q \vec{E} \) \( \vec{F}_E = (-e)(30 \hat{j}) = -30e \hat{j} \) \( \vec{F}_B = q (\vec{v} \times \vec{B}) \) \( \vec{F}_B = (-e) ((100 \hat{i}) \times (0.03 \hat{k})) \) \( \vec{F}_B = (-e) (3 (\hat{i} \times \hat{k})) = (-e) (3 (-\hat{j})) = 3e \hat{j} \)…
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