CUET · PHYSICS · PYQ PAPER 2023
An electron beam passes through a region of magnetic field of \( 2 \times 10^{-3} \text{ T} \) and an electric field of \( 3.2 \times 10^4 \text{ V m}^{-1} \), both acting perpendicular to each other. If the path of the electron remains undeviated calculate the speed of electron : [Mass of electron \( = 9.1 \times 10^{-31} \text{ kg} \)]
- A \( 0.8 \times 10^{6} \text{ m/s} \)
- B \( 0.8 \times 10^{7} \text{ m/s} \)
- C \( 1.6 \times 10^{6} \text{ m/s} \)
- D \( 1.6 \times 10^{7} \text{ m/s} \)
Answer & Solution
Correct Answer
(D) \( 1.6 \times 10^{7} \text{ m/s} \)
Step-by-step Solution
Detailed explanation
\( qE = qvB \) \( v = \frac{E}{B} \) \( v = \frac{3.2 \times 10^4}{2 \times 10^{-3}} \) \( v = 1.6 \times 10^7 \text{ m/s} \)
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