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CUET · PHYSICS · PYQ PAPER 2025

An electron accelerated with potential V has a de-Broglie wavelength \( \lambda \) associated with it. If the potential is changed to 4 V, the wavelength becomes

  1. A \( \lambda/4 \)
  2. B \( \lambda/2 \)
  3. C \( \lambda \)
  4. D \( 2\lambda \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( \lambda/2 \)

Step-by-step Solution

Detailed explanation

\( \lambda = \frac{h}{\sqrt{2meV}} \) \( \lambda' = \frac{h}{\sqrt{2me(4V)}} \) \( \lambda' = \frac{h}{\sqrt{4 \cdot 2meV}} \) \( \lambda' = \frac{1}{2} \frac{h}{\sqrt{2meV}} \) \( \lambda' = \frac{\lambda}{2} \)
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