CUET · PHYSICS · PYQ PAPER 2025
An electrical circuit contains a battery of V = 4 V, and a resistance of R = 2 \( \Omega \). A galvanometer of resistance G = 40 \( \Omega \) shunted by S = 10 \( \Omega \) is used to measure current in the circuit. The reading of ammeter is
- A 0.4 A
- B 2 A
- C 0 A
- D 0.1 A
Answer & Solution
Correct Answer
(A) 0.4 A
Step-by-step Solution
Detailed explanation
\( R_{p} = \frac{G \times S}{G + S} = \frac{40 \times 10}{40 + 10} = 8 \, \Omega \) \( R_{total} = R + R_{p} = 2 + 8 = 10 \, \Omega \) \( I = \frac{V}{R_{total}} = \frac{4}{10} = 0.4 \, A \)
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