CUET · PHYSICS · PYQ PAPER 2025
An electric dipole is placed at an angle of \(30^\circ\) with an electric field of intensity \(3 \times 10^5 \text{ N/C}\). It experiences a torque equal to \(6 \text{ N m}\). If the dipole length is 2 cm, the value of charge will be
- A \(5 \times 10^{-3} \text{ C}\)
- B \(8 \times 10^{-3} \text{ C}\)
- C \(6 \times 10^{-3} \text{ C}\)
- D \(2 \times 10^{-3} \text{ C}\)
Answer & Solution
Correct Answer
(D) \(2 \times 10^{-3} \text{ C}\)
Step-by-step Solution
Detailed explanation
\(q = \frac{\tau}{dE\sin\theta}\) \(q = \frac{6}{(0.02)(3 \times 10^5)\sin(30^\circ)}\) \(q = \frac{6}{(0.02)(3 \times 10^5)(0.5)}\) \(q = 2 \times 10^{-3} \text{ C}\)
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