CUET · PHYSICS · PYQ PAPER 2023
An e.m.f. \( e_s = 50 \sin(314t) \) is applied across a pure capacitor of \( 637 \ \mu\text{F} \).
The instantaneous current \( I \) is:
- A \( 10 \cos(314t) \text{ A} \)
- B \( 50 \cos(314t) \text{ A} \)
- C \( 20 \cos(314t) \text{ A} \)
- D \( 20 \sin(314t) \text{ A} \)
Answer & Solution
Correct Answer
(A) \( 10 \cos(314t) \text{ A} \)
Step-by-step Solution
Detailed explanation
\( I_m = V_m \omega C \) \( I_m = 50 \times 314 \times 637 \times 10^{-6} \approx 10 \text{ A} \) \( I = I_m \cos(\omega t) = 10 \cos(314t) \text{ A} \)
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