CUET · PHYSICS · PYQ PAPER 2025
An alternating voltage \( V = V_0 \sin(\omega t + \pi/2) \) is applied across an ac circuit. As a result, a current \( I = I_0 \sin(\omega t + \pi/6) \) flows in it. The power factor of the circuit is
- A zero
- B \(0.5\)
- C 1
- D \(\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(B) \(0.5\)
Step-by-step Solution
Detailed explanation
Phase of voltage: \( \phi_V = \pi/2 \) Phase of current: \( \phi_I = \pi/6 \) Phase difference: \( \phi = \phi_V - \phi_I = \pi/2 - \pi/6 = \pi/3 \) Power factor: \( \cos \phi = \cos(\pi/3) = 0.5 \)
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