CUET · PHYSICS · PYQ PAPER 2023
An alternating voltage \( V = 140 \sin 100\pi t \) is connected across a pure resistor of resistance \( 40 \, \Omega \). What is the rms current through the resistor? (Take \( \sqrt{2} = 1.4 \))
- A 3.5 A
- B 2.5 A
- C 4.9 A
- D 0.1 A
Answer & Solution
Correct Answer
(B) 2.5 A
Step-by-step Solution
Detailed explanation
\( V_0 = 140 \, V \) \( V_{rms} = \frac{V_0}{\sqrt{2}} = \frac{140}{1.4} = 100 \, V \) \( I_{rms} = \frac{V_{rms}}{R} = \frac{100}{40} = 2.5 \, A \)
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