CUET · PHYSICS · PYQ PAPER 2023
An alternating current is given by \( i = i_1 \cos \omega t + i_2 \sin \omega t \). The rms current is given by :
- A \( \frac{i_1 + i_2}{\sqrt{2}} \)
- B \( \frac{|i_1 + i_2|}{\sqrt{2}} \)
- C \( \sqrt{\frac{i_1^2 + i_2^2}{2}} \)
- D \(\sqrt{\frac{i_1^2+i_2^2}{\sqrt{2}}}\)
Answer & Solution
Correct Answer
(C) \( \sqrt{\frac{i_1^2 + i_2^2}{2}} \)
Step-by-step Solution
Detailed explanation
\( I_{peak} = \sqrt{i_1^2 + i_2^2} \) \( I_{rms} = \frac{I_{peak}}{\sqrt{2}} = \frac{\sqrt{i_1^2 + i_2^2}}{\sqrt{2}} = \sqrt{\frac{i_1^2 + i_2^2}{2}} \)
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