CUET · PHYSICS · PYQ PAPER 2023
An alpha-particle moves with a speed of \( (5 \times 10^5 \hat{i}) \text{ m s}^{-1} \).
It enters a region where there is a magnetic field of magnitude 4 T,
directed at an angle of 45° to the X-axis and lying in the XY-plane.
The magnitude of magnetic force on the alpha-particle is:
- A \( 1.6 \times 10^{-14} \text{ N} \)
- B \( 3.2 \times 10^{-13} \text{ N} \)
- C \( 4.5 \times 10^{-13} \text{ N} \)
- D \( 1.6 \times 10^{-13} \text{ N} \)
Answer & Solution
Correct Answer
(C) \( 4.5 \times 10^{-13} \text{ N} \)
Step-by-step Solution
Detailed explanation
\( F = q v B \sin \theta \) \( F = (2 \times 1.6 \times 10^{-19} \text{ C}) (5 \times 10^5 \text{ m s}^{-1}) (4 \text{ T}) \sin 45^\circ \) \( F = (3.2 \times 10^{-19}) (5 \times 10^5) (4) \frac{1}{\sqrt{2}} \text{ N} \)…
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