CUET · PHYSICS · PYQ PAPER 2025
A yellow LED of power 0.2 W emits light uniformly around it. The amplitude of the electric field of light at a distance of 2 m from the LED is:
- A 2.45 V/m
- B 5.48 V/m
- C 4.9 V/m
- D 1.73 V/m
Answer & Solution
Correct Answer
(D) 1.73 V/m
Step-by-step Solution
Detailed explanation
\(E_0=\sqrt{2 \cdot I \cdot(120 \pi)}\) \(E_0=\sqrt{2 \cdot\left(\frac{0.2}{16 \pi}\right) \cdot 120 \pi}\) \(E_0=\sqrt{\frac{0.4 \times 120}{16}}\) \(E_0=\sqrt{\frac{48}{16}}=\sqrt{3}\) \(E_0 \approx 1.732 V / m\)
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