CUET · PHYSICS · PYQ PAPER 2025
A wire carries a current of 2.0 A. The number of electrons crossing through its cross-section in 10 s will be
- A \( 1.6 \times 10^{19} \)
- B \( 1.25 \times 10^{18} \)
- C \( 2.5 \times 10^{20} \)
- D \( 1.25 \times 10^{20} \)
Answer & Solution
Correct Answer
(D) \( 1.25 \times 10^{20} \)
Step-by-step Solution
Detailed explanation
\( n = \frac{It}{e} \) \( n = \frac{(2.0 \text{ A})(10 \text{ s})}{1.6 \times 10^{-19} \text{ C}} \) \( n = 1.25 \times 10^{20} \)
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