CUET · PHYSICS · PYQ PAPER 2023
A TV tower has a height of 20 m and the radius of earth is \(6.4 \times 10^6 m\). The range of the tower is:
- A 32 km
- B 16 km
- C 40 km
- D \(40 \sqrt{2} km\)
Answer & Solution
Correct Answer
(B) 16 km
Step-by-step Solution
Detailed explanation
\(d = \sqrt{2hR}\) \(d = \sqrt{2 \times 20 \text{ m} \times 6.4 \times 10^6 \text{ m}}\) \(d = \sqrt{256 \times 10^6 \text{ m}^2}\) \(d = 16 \times 10^3 \text{ m}\) \(d = 16 \text{ km}\)
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