CUET · PHYSICS · PYQ PAPER 2025
A transformer has 1000 turns in the primary and 2000 turns in its secondary winding. The primary voltage is 200 V and the load across the secondary is \(100 \Omega\). If the transformer is assumed to be ideal, then the value of current in the primary is
- A \(4.0 A\)
- B \(2.5 A\)
- C \(5.0 A\)
- D \(8.0 A\)
Answer & Solution
Correct Answer
(D) \(8.0 A\)
Step-by-step Solution
Detailed explanation
\(V_s = V_p \frac{N_s}{N_p} = 200 V \times \frac{2000}{1000} = 400 V\) \(I_s = \frac{V_s}{R_s} = \frac{400 V}{100 \Omega} = 4 A\) \(I_p = \frac{V_s I_s}{V_p} = \frac{400 V \times 4 A}{200 V} = 8 A\)
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