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CUET · PHYSICS · PYQ PAPER 2023

A straight wire of length 2 m and mass 50 g carrying a current of 4 A is balanced in air with the force due to uniform magnetic field acting perpendicular to the length of the wire. The magnitude of magnetic field is:

  1. A \(3.2 \times 10^{-2}\) T
  2. B \(6.1 \times 10^{-2}\) T
  3. C \(4.9 \times 10^{-1}\) T
  4. D \(6.1 \times 10^{-3}\) T
Verified Solution

Answer & Solution

Correct Answer

(B) \(6.1 \times 10^{-2}\) T

Step-by-step Solution

Detailed explanation

\(BIL = mg \Rightarrow B = \frac{mg}{IL}\) \(B = \frac{0.05 \text{ kg} \times 9.8 \text{ m/s}^2}{4 \text{ A} \times 2 \text{ m}} = 0.06125 \text{ T}\) \(B = 6.1 \times 10^{-2} \text{ T}\)