CUET · PHYSICS · PYQ PAPER 2023
A straight current carrying copper wire with 28 Ampere current is held normal to the magnetic field such that the copper wire is balanced against gravity acting on it. Find the value of magnetic field if mass per unit length of wire is (46.6 gram/meter).
- A 3.5 \(\times 10^{-2}\) T
- B 1.6 \(\times 10^{-2}\) T
- C 3.8 \(\times 10^{-2}\) T
- D 1.8 \(\times 10^{-3}\) T
Answer & Solution
Correct Answer
(B) 1.6 \(\times 10^{-2}\) T
Step-by-step Solution
Detailed explanation
\(F_B = F_G\) \(BIL = mg\) \(B = \frac{(m/L)g}{I}\) \(B = \frac{(46.6 \times 10^{-3} \text{ kg/m})(9.8 \text{ m/s}^2)}{28 \text{ A}}\) \(B = 1.631 \times 10^{-2} \text{ T}\)
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