CUET · PHYSICS · PYQ PAPER 2025
A small charged water drop with charge \( q = 1.5 \times 10^{-6} \text{ C} \) and mass m = 10 g is suspended in air in electric field E. The value of E is given by (Take acceleration due to gravity \( g = 10 \text{ m s}^{-2} \))
- A \( 10.2 \times 10^6 \text{ N/C} \)
- B \( 1.5 \times 10^6 \text{ N/C} \)
- C \(1.5 \times 10^{-4} N / C\)
- D \( 6.67 \times 10^4 \text{ N/C} \)
Answer & Solution
Correct Answer
(D) \( 6.67 \times 10^4 \text{ N/C} \)
Step-by-step Solution
Detailed explanation
\( qE = mg \) \( E = \frac{mg}{q} \) \( E = \frac{(10 \times 10^{-3} \text{ kg})(10 \text{ m s}^{-2})}{1.5 \times 10^{-6} \text{ C}} \) \( E = \frac{0.1}{1.5 \times 10^{-6}} \) \( E \approx 6.67 \times 10^4 \text{ N/C} \)
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