CUET · PHYSICS · PYQ PAPER 2023
A slit of width 'd' is illuminated by red light of wavelength 650 nm. What should be the value of slit width 'd' so that first minimum fall at an angle of diffraction of \(\frac{\pi}{6}\) ?
- A \(1.3 \times 10^{-6} m\)
- B \(1.3 \times 10^{-5} m\)
- C \(6.5 \times 10^{-6} m\)
- D \(7.5 \times 10^{-6} m\)
Answer & Solution
Correct Answer
(A) \(1.3 \times 10^{-6} m\)
Step-by-step Solution
Detailed explanation
\(d \sin \theta = n \lambda\) \(d \sin\left(\frac{\pi}{6}\right) = 1 \times 650 \times 10^{-9} \text{ m}\) \(d \times 0.5 = 650 \times 10^{-9} \text{ m}\) \(d = \frac{650 \times 10^{-9}}{0.5} = 1.3 \times 10^{-6} \text{ m}\)
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