CUET · PHYSICS · PYQ PAPER 2025
A slit is illuminated by light of wavelength \( 6500 \text{ \AA} \).
The first minimum is observed at \( \theta = 30^\circ \). The width of the slit is:
- A 13 \( \mu\text{m} \)
- B 3.25 \( \mu\text{m} \)
- C 1.3 \( \mu\text{m} \)
- D 1.7 \( \mu\text{m} \)
Answer & Solution
Correct Answer
(C) 1.3 \( \mu\text{m} \)
Step-by-step Solution
Detailed explanation
\( a \sin \theta = \lambda \) \( a = \frac{6500 \times 10^{-10} \text{ m}}{\sin 30^\circ} \) \( a = \frac{6500 \times 10^{-10}}{0.5} = 13000 \times 10^{-10} \text{ m} \) \( a = 1.3 \times 10^{-6} \text{ m} = 1.3\)\(\mu m\)
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