CUET · PHYSICS · PYQ PAPER 2023
A slab of material of dielectric constant \( k \), having the same area as the plate of a parallel plate capacitor but has a thickness \( \frac{3}{5} \) of the distance between the plates \( d \), is inserted between the plates of the capacitor. When there is air between the plates, the potential difference is \( V_0 \). What is the potential difference between the plates of the capacitor after inserting the dielectric?
- A \( \left( \frac{2k + 3}{k} \right) V_0 \)
- B \( \left( \frac{2k + 3}{5k} \right) V_0 \)
- C \( \left( \frac{5k}{2k + 3} \right) V_0 \)
- D \( \left( \frac{k + 3}{5k} \right) V_0 \)
Answer & Solution
Correct Answer
(B) \( \left( \frac{2k + 3}{5k} \right) V_0 \)
Step-by-step Solution
Detailed explanation
\( Q = C_0 V_0 = \frac{\epsilon_0 A V_0}{d} \) \( C = \frac{\epsilon_0 A}{d - t + \frac{t}{k}} = \frac{\epsilon_0 A}{d - \frac{3}{5}d + \frac{\frac{3}{5}d}{k}} \)…
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