CUET · PHYSICS · PYQ PAPER 2025
A short bar magnet placed with its axis at \(30^\circ\) with a uniform external magnetic field of 0.16 T experiences a torque of magnitude 0.48 J. The magnetic moment of the bar magnet will be
- A \(6 J/T\)
- B \(0.4J/T\)
- C \(8J/T\)
- D \(1.5 J/T\)
Answer & Solution
Correct Answer
(A) \(6 J/T\)
Step-by-step Solution
Detailed explanation
\(\tau = MB \sin\theta\) \(M = \frac{\tau}{B \sin\theta}\) \(M = \frac{0.48 \text{ J}}{0.16 \text{ T} \times \sin(30^\circ)}\) \(M = \frac{0.48 \text{ J}}{0.16 \text{ T} \times 0.5}\) \(M = \frac{0.48 \text{ J}}{0.08 \text{ T}}\) \(M = 6 \text{ J/T}\)
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