CUET · PHYSICS · PYQ PAPER 2023
A short bar magnet of magnetic dipole moment \( 10^{-5} \text{ A m}^{2} \) is kept in a uniform magnetic field \( 3 \times 10^{-4} \text{ T} \) at an angle of \( 30^{\circ} \). The torque acting on it is :
- A \( 1.5 \times 10^{-9} \text{ Nm} \)
- B \( 3 \times 10^{-9} \text{ Nm} \)
- C \( 1.5 \times 10^{-5} \text{ Nm} \)
- D \( 3 \times 10^{-5} \text{ Nm} \)
Answer & Solution
Correct Answer
(A) \( 1.5 \times 10^{-9} \text{ Nm} \)
Step-by-step Solution
Detailed explanation
\( \tau = MB \sin\theta \) \( \tau = (10^{-5} \text{ A m}^{2})(3 \times 10^{-4} \text{ T}) \sin(30^{\circ}) \) \( \tau = (3 \times 10^{-9}) (0.5) \text{ Nm} \) \( \tau = 1.5 \times 10^{-9} \text{ Nm} \)
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