CUET · PHYSICS · PYQ PAPER 2025
A series LCR circuit is connected to a 230 V, 50 rad/s source. Given L = 5 H, C = 80 \( \mu \)F and R = 40 \( \Omega \). Impedance of the circuit is
- A \( 40 \text{ } \Omega \)
- B \( 50 \text{ } \Omega \)
- C \( 100 \text{ } \Omega \)
- D \( 250 \text{ } \Omega \)
Answer & Solution
Correct Answer
(A) \( 40 \text{ } \Omega \)
Step-by-step Solution
Detailed explanation
\(X_L = \omega L = 50 \times 5 = 250 \text{ } \Omega \) \(X_C = \frac{1}{\omega C} = \frac{1}{50 \times 80 \times 10^{-6}} = 250 \text{ } \Omega \) \(Z = \sqrt{R^2 + (X_L - X_C)^2} = \sqrt{40^2 + (250 - 250)^2} = 40 \text{ } \Omega \)
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