CUET · PHYSICS · PYQ PAPER 2023
A resistor develops 200 J of thermal energy in 5 s when a current of 2 A is passed through it. If the current is measured to 5 A, what will be the energy developed in 12 s ?
- A 1920 J
- B 3000 J
- C 6000 J
- D 4000 J
Answer & Solution
Correct Answer
(B) 3000 J
Step-by-step Solution
Detailed explanation
\(R = E_1 / (I_1^2 t_1)\) \(R = 200 \text{ J} / ((2 \text{ A})^2 \times 5 \text{ s}) = 10 \Omega\) \(E_2 = I_2^2 R t_2\) \(E_2 = (5 \text{ A})^2 \times 10 \Omega \times 12 \text{ s} = 3000 \text{ J}\)
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