CUET · PHYSICS · PYQ PAPER 2025
A radiation of energy E is normally incident on a perfectly reflecting surface. The momentum transferred to the surface will be: (Given: speed of light c)
- A \(\frac{E}{c}\)
- B \(\frac{2E}{c}\)
- C \(\frac{E}{c^2}\)
- D \(\frac{2E}{c^2}\)
Answer & Solution
Correct Answer
(B) \(\frac{2E}{c}\)
Step-by-step Solution
Detailed explanation
Incident radiation momentum: \(p = \frac{E}{c}\) For perfect reflection, momentum transferred to surface: \(2p\) Result: \(\frac{2E}{c}\)
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